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Derive integrated rate law for zero order reaction.

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Question

Derive integrated rate law for zero order reaction.

Derivation
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Solution

Consider a zero-order reaction, \[\ce{A -> Product}\]

The rate of the reaction is:

Rate = `-(d[A])/dt`

By the rate law,

Rate = k × [A]0 = k

On rearranging the equation,

∴ d[A] = k × dt

If [A]0 is the initial concentration of the reactant A at t = 0 and [A]t is the concentration of A present after time t, then by integrating the above equation,

`int_([A]_0)^([A]_t) - d[A] = int_(t = 0)^(t = t) k  dt`

`- int_([A]_0)^([A]_t) d  [A] = kint_(0)^(t) dt`

`[A]_([A]_0)^([A]_t) = k [t]_0^t`

−([A]t − [A]0) = kt

∴ [A]0 − [A]t = kt

∴ k = `([A]_0 - [A]_t)/t`

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