English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Depict the galvanic cell in which the reaction \\ce{Zn(s) + 2Ag+(aq) → Zn^{2+}(aq) + 2Ag(s)}\ takes place. Further show: (i) Which of the electrode is negatively charged? - Chemistry

Advertisements
Advertisements

Question

Depict the galvanic cell in which the reaction \[\ce{Zn(s) + 2Ag+(aq) → Zn^{2+}(aq) + 2Ag(s)}\] takes place. Further show:

  1. Which of the electrode is negatively charged?
  2. The carriers of the current in the cell.
  3. Individual reaction at each electrode.
Chemical Equations/Structures
Short Answer
Advertisements

Solution

The set-up will be similar to as shown below:

The cell will be represented as:

\[\ce{Zn(s) | Zn^{2+}(aq) || Ag^+(aq) | Ag(s)}\]

  1. Anode, i.e., zinc electrode, will be negatively charged.
  2. The current will flow from silver to zinc in the external circuit.
  3. At anode: \[\ce{Zn(s) -> Zn^{2+}(aq) + 2e–}\]
    At cathode: \[\ce{Ag+(aq) + e– -> Ag(s)}\]
shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Electrochemistry - Exercises [Page 59]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.3 | Page 59

RELATED QUESTIONS

Draw a neat and well labelled diagram of primary reference electrode.


Can copper sulphate solution be stored in an iron vessel? Explain.


The standard e.m.f of the following cell is 0.463 V

`Cu|Cu_(1m)^(++)`

What is the standard potential of Cu electrode?

(A) 1.137 V

(B) 0.337 V

(C) 0.463 V

(D) - 0.463 V


Calculate E°cell for the following reaction at 298 K:

2Al(s) + 3Cu+2(0.01M) → 2Al+3(0.01M) + 3Cu(s)

Given: Ecell = 1.98V


Calculate emf of the following cell at 25°C:

\[\ce{Sn/Sn^2+ (0.001 M) || H+ (0.01 M) | H2_{(g)} (1 bar) | Pt_{(s)}}\]

Given: \[\ce{E^\circ(Sn^2+/sn) = -0.14 V, E^\circ H+/H2 = 0.00 V (log 10 = 1)}\]


Given the standard electrode potentials,

K+/K = −2.93 V, Ag+/Ag = 0.80 V,

Hg2+/Hg = 0.79 V

Mg2+/Mg = −2.37 V, Cr3+/Cr = −0.74 V

Arrange these metals in their increasing order of reducing power.


Calculate the emf of the following cell at 25°C :

\[{E^0}_\left( {Zn}^{2 +} /Zn \right) = - 0 . 76 V, {E^0}_\left( H^+ / H_2 \right) = 0 . 00 V\]

 


Galvanic or a voltaic cell converts the chemical energy liberated during a redox reaction to ____________.


Standard hydrogen electrode operated under standard conditions of 1 atm Hpressure, 298 K, and pH = 0 has a cell potential of ____________.


Which cell will measure standard electrode potential of copper electrode?


The positive value of the standard electrode potential of Cu2+/Cu indicates that:

(i) this redox couple is a stronger reducing agent than the H+/H2 couple.

(ii) this redox couple is a stronger oxidising agent than H+/H2 .

(iii) Cu can displace H2 from acid.

(iv) Cu cannot displace H2 from acid.


Assertion: Cu is less reactive than hydrogen.

Reason: `E_((Cu^(2+))/(Cu))^Θ` is negative.


Standard reduction potentials (E°) of Cd2+, respectively which is the strongest reducing agent 


A voltaic cell is made by connecting two half cells represented by half equations below:

\[\ce{Sn^{2+}_{ (aq)} + 2e^- -> Sn_{(s)}}\], E0 = − 0.14 V

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E0 = + 0.77 V

Which statement is correct about this voltaic cell?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×