English

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans

Advertisements
Advertisements

Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans of paint will she need to paint the room?

Sum
Advertisements

Solution

Given that,

Length (l) = 15 m,

breadth (b) = 10 m,

height (h) = 7 m

Area of the hall to be painted = Area of the wall + Area of the ceiling

= 2h (l + b) + lb

= [2(7) (15 + 10) + 15 ×10] m2

= [14(25) + 150] m2

= [350 + 150] m2

= 500 m2

It is given that 100 m2 area can be painted from each can.

Number of cans required to paint an area of 500 m2

= `500/100`

= 5 cans

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×