Advertisements
Advertisements
प्रश्न
Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans of paint will she need to paint the room?
Advertisements
उत्तर
Given that,
Length (l) = 15 m,
breadth (b) = 10 m,
height (h) = 7 m
Area of the hall to be painted = Area of the wall + Area of the ceiling
= 2h (l + b) + lb
= [2(7) (15 + 10) + 15 ×10] m2
= [14(25) + 150] m2
= [350 + 150] m2
= 500 m2
It is given that 100 m2 area can be painted from each can.
Number of cans required to paint an area of 500 m2
= `500/100`
= 5 cans
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.
APPEARS IN
संबंधित प्रश्न
Find the height of a cuboid whose base area is 180 cm2 and volume is 900 cm3?
A 4 cm edge cube is cut into 1 cm edge cubes. Calculate the total surface area of all the small cubes.
A cuboidal block of solid iron has dimensions 50 cm, 45 cm and 34 cm. How many cuboids of size 5 cm by 3 cm by 2 cm can be obtained from this block? Assume cutting causes no wastage.
How many bricks each of size 25 cm × 10 cm × 8 cm will be required to build a wall 5 m long, 3 m high and 16 cm thick, assuming that the volume of sand and cement used in the construction is negligible?
A swimming pool is 20 m long 15 m wide and 3 m deep. Find the cost of repairing the floor and wall at the rate of Rs 25 per square metre.
The areas of three adjacent faces of a cuboid are x, y and z. If the volume is V, prove that V2 = xyz.
The dimensions of a room are 12.5 m by 9 m by 7 m. There are 2 doors and 4 windows in the room; each door measures 2.5 m by 1.2 m and each window 1.5 m by 1 m. Find the cost of painting the walls at Rs 3.50 per square metre.
If the volumes of two cubes are in the ratio 8: 1, then the ratio of their edges is
The cost of constructing a wall 8 m long, 4 m high and 10 cm thick at the rate of Rs. 25 per m3 is
All six faces of a cuboid are ______ in shape and of ______ area.
