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Question
Convert the given frequency distribution into a continuous grouped frequency distribution:
| Class interval | Frequency |
| 150 – 153 | 7 |
| 154 – 157 | 7 |
| 158 – 161 | 15 |
| 162 – 165 | 10 |
| 166 – 169 | 5 |
| 170 – 173 | 6 |
In which intervals would 153.5 and 157.5 be included?
Sum
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Solution
It is clear that, the given table is in inclusive (discontinuous) form.
So, we first convert it into exclusive form.
Now, consider the classes 150 – 153, 154 – 157.
Lower limit of 154 – 157 = 154 and upper limit of 150 – 153 = 153
Required difference = 154 – 153 = 1
So, half the difference = `1/2` = 0.5
So, we subtract 0.5 from each lower limit and add 0.5 to each upper limit.
The table for continuous grouped frequency distribution is given below:
| Class interval | Frequency |
| 149.5 – 153.5 | 7 |
| 153.5 – 157.5 | 7 |
| 157.5 – 161.5 | 15 |
| 161.5 – 165.5 | 10 |
| 165.5 – 169.5 | 5 |
| 169.5 – 173.5 | 6 |
Thus, 153.5 and 157.5 would use in the class intervals 153.5 – 157.5 and 157.5 – 161.5, respectively.
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