Advertisements
Advertisements
प्रश्न
Convert the given frequency distribution into a continuous grouped frequency distribution:
| Class interval | Frequency |
| 150 – 153 | 7 |
| 154 – 157 | 7 |
| 158 – 161 | 15 |
| 162 – 165 | 10 |
| 166 – 169 | 5 |
| 170 – 173 | 6 |
In which intervals would 153.5 and 157.5 be included?
योग
Advertisements
उत्तर
It is clear that, the given table is in inclusive (discontinuous) form.
So, we first convert it into exclusive form.
Now, consider the classes 150 – 153, 154 – 157.
Lower limit of 154 – 157 = 154 and upper limit of 150 – 153 = 153
Required difference = 154 – 153 = 1
So, half the difference = `1/2` = 0.5
So, we subtract 0.5 from each lower limit and add 0.5 to each upper limit.
The table for continuous grouped frequency distribution is given below:
| Class interval | Frequency |
| 149.5 – 153.5 | 7 |
| 153.5 – 157.5 | 7 |
| 157.5 – 161.5 | 15 |
| 161.5 – 165.5 | 10 |
| 165.5 – 169.5 | 5 |
| 169.5 – 173.5 | 6 |
Thus, 153.5 and 157.5 would use in the class intervals 153.5 – 157.5 and 157.5 – 161.5, respectively.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
