Question

Construct a trapezium ABCD in which AD//BC, AB = CD = 3.6 cm, BC = 5 cm and AD = 4.5 cm.

Answer 1

Given: AB = CD = 3.6 cm, BC = 5 cm and AD = 4.5 cm

To construct the trapezium steps are:

• Draw a line segment BC = 5 cm [Establishing the base of the trapezium]
• Mark a point E on BC such that EC = 4.5 cm, making BE = 0.5 cm} [Setting up the base for auxiliary triangle ABE]
• With B as center and radius 3.6 cm, draw an arc [Marking the distance for side AB]
• With E as center and radius 3.6 cm, draw another arc intersecting the first at A [Locating vertex A using property AE || CD]
• With A as center and radius 4.5 cm, draw an arc [Marking the distance for parallel top base AD]
• With C as center and radius 3.6 cm, draw another arc intersecting the previous arc at D [Locating vertex D to complete the trapezium]
• Join AB, AD, and CD [Closing the figure to form trapezium ABCD]