Advertisements
Advertisements
Question
Construct a parallelogram ABCD, when:
Base BC = 5.6 cm, diagonal BD = 6.5 cm and altitude = 3.2 cm.
Advertisements
Solution
Steps:
1. Draw BC = 5.6 cm.
2. At C, draw CX perpendicular to BC.
3. with C as a centre and taking radius 3.2 cm to draw an arc to cut CX at Y.
4. Through Y draw a straight line PQ parallel to BC.
5. With B as a centre and radius, 6.5 cm draw an arc to meet PQ at D.
6. With D as a centre and radius equal to 5.6 cm, draw an arc to meet PQ at A.
7. Join BA, BD and CD.
ABCD is the required parallelogram.
APPEARS IN
RELATED QUESTIONS
Construct a parallelogram ABCD, when:
Diagonal AC = 6.4 cm, diagonals BD = 8.2 cm and angle between the diagonals = 60°.
Construct a parallelogram ABCD, when:
AB = 5.8 cm, diagonal AC = 8.2 cm and diagonal BD = 6.2 cm.
Construct a parallelogram ABCD, when:
Base AB = 6.5 cm, BC = 4 cm and the altitude corresponding to AB = 3.1 cm.
Construct a parallelogram ABCD, if :
BC = 4.5 cm, CD = 5.2 cm and ∠ADC = 75°.
Construct a parallelogram ABCD, if :
AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
Construct a parallelogram ABCD, if :
diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 5.4 cm and 6.7 cm respectively and the angle between them is 60°.
Draw a parallelogram ABCD, with AB = 6 cm, AD = 4.8 cm and ∠DAB = 45°. Draw the perpendicular bisector of side AD and let it meet AD at point P. Also, draw the diagonals AC and BD; and let them intersect at point O. Join O and P. Measure OP.
Construct a parallelogram ABCD. Given:
AB = 5.5cm, BC = 3.5cm, ∠B = 75°
Construct a parallelogram ABCD in which AB = 4.5cm, ∠A = 105° and the distance between AB and CD is 3.2cm.
