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Question
Complete the following equation describing nuclear decay.
\[\ce{_88^226Ra->_2^4\alpha {+}}\] ______.
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Solution
\[\ce{_88^226Ra->_2^4\alpha{ +} \underline{\ce{_86^222Em}}}\]
Em (Emanation) ≡ Rn (Radon)
Here, α particle is emitted, and radon is formed.
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