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Question
Classify the following carbon compounds into two homologous series and name them.
C3H4, C3H6, C4H6, C4H8, C5H8, C5H10
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Solution
The given carbon compounds can be classified into the following two homologous series:-
a) Alkenes:- Propene C3H6, Butene C4H8, Pentene C5H10
b) Alkynes:- Propyne C3H4, Butyne C4H6, Pentyne C5H8
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RELATED QUESTIONS
Write the name and formula of the 2nd member of homologous series having general formula CnH2n + 2.
Define a homologous series. Give the name and structural formula of one homologue of the following:
CH3OH
Write the molecular formula of the third member of the homologous series of carbon compounds with general formula CnHO2n+1OH.
The number of carbon atoms present in the molecule of fifth member of the homologous series of alkynes is:
(a) four
(b) five
(c) six
(d) seven
Write the name and molecular formula of the first member of the homologous series of alkynes.
Give the names of the first four members of the homologous series of
alkynes.
What is a homologous series?
Assertion (A): In a homologous series of alcohols, the formula for the second member is C2H5OH and the third member is C3H7OH.
Reason (R): The difference between the molecular masses of the two consecutive members of a homologous series is 144.
Complete the correlation:
Alkene : C = C :: Alkyne: _______.
Consider the following molecular formulae of carbon compounds:
(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8
- Which one of these compounds belongs to homologous series of alcohols?
- Identify the compound having triple bond between carbon-carbon atoms.
- Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
- Write the general formula of the series to which the compound C4H8 belongs.
