Advertisements
Advertisements
Question
Calculate the cost of operating a heater of 500 W for 20 hours at the rate of Rs 3.90 per unit.
Advertisements
Solution
Power rating of the heater, P = 500 W
Duration of the operation, t = 20 hours
Electrical energy consumed = P × t
= 500 W × 20 hours
= 10000 W
= 10 kW
Rate for 1 kW = Rs. 3.90
Total cost of operating = Units consumed × Rate
= 10 × Rs. 3.90
= Rs. 39
RELATED QUESTIONS
Which particles are responsible for current in conductors?
Define watt. Write down an equation linking watts, volts and amperes.
How many joules are there in one kilowatt-hour?
The diagram below shows a magnetic kept just below the conductor AB which is kept in North South direction.

(i) In which direction will the needle deflect when the key is closed ?
(ii) Why is the deflection produced ?
(iii) What will be the change in the deflection if the magnetic needle is taken just above the conductor AB ?
(iv) Name one device which works on this principle.
An electric bulb of resistance 500 Ω draws current 0.4 A from the source. Calculate:
- the power of bulb and
- the potential difference at its end.
Two electric lamps each rating 100 W, 110 V are connected in series to a 220 V power supply and two other electric lamps each of marking 100 W, 220 V are connected in parallel to the same power supply. Will anyone of the two combinations give more light than the other? Give a reason for your answer.
Why is the electric power from the generating station transmitted at high voltage?
Two resistances R1 = 4Ω and R2 = 6Ω are connected in series. The combination is connected with a battery of e.m.f. 6V and negligible resistance. Calculate:
(i) the heat produced per minute in each resistor,
(ii) the power supplied by the battery.
