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Question
Calculate De Broglie's wavelength of the bullet moving with speed 90m/sec and having a mass of 5 gm.
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Solution
Given: v = 90 m/s, m = 5 g = 5 × 10-3 kg
To find: De Broglie wavelength (λ)
Formula: `lambda = "h"/"mv"`
Calculation:
λ = `(6.63 xx 10^-34)/((5 xx 10^-3) (90))`
= 0.0147 × 10-31
`= 1.47 xx 10^-33` m
De Broglie wavelength of given bullet is 1.473 × 10-33 m.
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