Advertisements
Advertisements
Question
An electron is accelerated through a potential difference of 100 volts. Calculate de-Broglie wavelength in nm.
Advertisements
Solution
V = 100 volts
∴ `lambda = 1.228/sqrt"V" = 1.228/sqrt100 = 1.228/10 = 0.1228` nm
APPEARS IN
RELATED QUESTIONS
An electron, a proton, an α-particle, and a hydrogen atom are moving with the same kinetic energy. The associated de Broglie wavelength will be longest for ______.
State the importance of Davisson and Germer experiment.
What is the speed of a proton having de Broglie wavelength of 0.08 Å?
The de Broglie wavelengths associated with an electron and a proton are the same. What will be the ratio of
- their momenta
- their kinetic energies?
Two particles have the same de Broglie wavelength and one is moving four times as fast as the other. If the slower particle is an α-particle, what are the possibilities for the other particle?
Find the ratio of the de Broglie wavelengths of an electron and a proton when both are moving with the (a) same speed, (b) the same kinetic energy, and (c) the same momentum. State which of the two will have a longer wavelength in each case.
According to De-Broglie, the waves are associated with ______
An electron is accelerated through a potential of 120 V. Find its de Broglie wavelength.
The de Broglie wavelength associated with photon is, ____________.
If the radius of the innermost Bohr orbit is 0.53 Å, the radius of the 4th orbit is ______
An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is ( c being velocity of light) ______.
What is the momentum of a photon having frequency 1.5 x 1013 Hz?
If the radius of the circular path and frequency of revolution of a particle of mass m are doubled, then the change in its kinetic energy will be (Ei and Ef are the initial and final kinetic energies of the particle respectively.)
How much energy is imparted to an electron so that its de-Broglie wavelength reduces from 10-10 m to 0.5 × 10-10 m? (E =energy of electron)
The wavelength '`lambda`' of a photon and de-Broglie wavelength of an electron have same value. The ratio of energy of a photon to kinetic energy of electron is (m = mass of electron, c = velocity of light, h = Planck's constant) ____________.
Graph shows the variation of de-Broglie wavelength `(lambda)` versus `1/sqrt"V"`, where 'V' is the accelerating potential for four particles carrying same charge but of masses m1 , m2, m3, m4. Which particle has a smaller mass?

According to de-Broglie hypothesis, the ratio of wavelength of an electron and that of photon having same energy 'E' is (m = mass of electron, c = velocity of light) ____________.
A photon of wavelength 3315 Å falls on a photocathode and an electron of energy 3 x 10-19 J is ejected. The threshold wavelength of photon is [Planck's constant (h) = 6.63 x 10-34 J.s, velocity of light (c) = 3 x 108 m/s] ____________.
Explain de-Broglie wavelength.
An electron of mass m has de-Broglie wavelength λ when accelerated through potential difference V. When proton of mass M, is accelerated through potential difference 9V, the de-Broglie wavelength associated with it will be ______. (Assume that wavelength is determined at low voltage)
A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as ______.
A photon and an electron have an equal energy ‘E’. The ratio of wavelength ‘λp’ of photon to that of electron ‘λe’ is proportional to ______.
