Advertisements
Advertisements
प्रश्न
Calculate De Broglie's wavelength of the bullet moving with speed 90m/sec and having a mass of 5 gm.
Advertisements
उत्तर
Given: v = 90 m/s, m = 5 g = 5 × 10-3 kg
To find: De Broglie wavelength (λ)
Formula: `lambda = "h"/"mv"`
Calculation:
λ = `(6.63 xx 10^-34)/((5 xx 10^-3) (90))`
= 0.0147 × 10-31
`= 1.47 xx 10^-33` m
De Broglie wavelength of given bullet is 1.473 × 10-33 m.
संबंधित प्रश्न
State the importance of Davisson and Germer experiment.
Explain what you understand by the de Broglie wavelength of an electron. Will an electron at rest have an associated de Broglie wavelength? Justify your answer.
Two particles have the same de Broglie wavelength and one is moving four times as fast as the other. If the slower particle is an α-particle, what are the possibilities for the other particle?
According to De-Broglie, the waves are associated with ______
An electron is accelerated through a potential of 120 V. Find its de Broglie wavelength.
Explain De Broglie’s Hypothesis.
The momentum of a photon of energy 1 MeV in kg m/s will be ______
The de Broglie wavelength associated with photon is, ____________.
If the radius of the innermost Bohr orbit is 0.53 Å, the radius of the 4th orbit is ______
According to de-Broglie hypothesis, the wavelength associated with moving electron of mass 'm' is 'λe'· Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is 'λp'. If the energy (E) of electron and photon is same then relation between 'λe' and 'λp' is ______.
What is the momentum of a photon having frequency 1.5 x 1013 Hz?
A particle of charge q, mass m and energy E has de-Broglie wavelength `lambda.` For a particle of charge 2q, mass 2m and energy 2E, the de-Broglie wavelength is ____________.
If '`lambda_1`' and '`lambda_2`' are de-Broglie wavelengths for electrons in first and second Bohr orbits in hydrogen atom, then the ratio '`lambda_2`' to '`lambda_1`' is (E1 = -13.6 eV) ____________.
If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with the electrons change?
According to de-Broglie hypothesis, the ratio of wavelength of an electron and that of photon having same energy 'E' is (m = mass of electron, c = velocity of light) ____________.
A photon of wavelength 3315 Å falls on a photocathode and an electron of energy 3 x 10-19 J is ejected. The threshold wavelength of photon is [Planck's constant (h) = 6.63 x 10-34 J.s, velocity of light (c) = 3 x 108 m/s] ____________.
Obtain an expression for de-Broglie wavelength of wave associated with material particles. The photoelectric work function for metal is 4.2 eV. Find the threshold wavelength.
A proton, a neutron, an electron and an α-particle have same energy. λp, λn, λe and λα are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following :
The energy of an electron having de-Broglie wavelength `λ` is ______.
(h = Plank's constant, m = mass of electron)
An electron of mass m has de-Broglie wavelength λ when accelerated through potential difference V. When proton of mass M, is accelerated through potential difference 9V, the de-Broglie wavelength associated with it will be ______. (Assume that wavelength is determined at low voltage)
An electron is accelerated through a potential difference of 100 volts. Calculate de-Broglie wavelength in nm.
