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प्रश्न
State the importance of Davisson and Germer experiment.
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उत्तर
The Davisson and Germer experiment are probably one of the most important experiments ever since it substantiated de Broglie’s hypothesis of wave-particle duality. It verified that De Broglie's “matter wave” hypothesis applied to matter (electrons) as well as light.
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संबंधित प्रश्न
The de Broglie wavelengths associated with an electron and a proton are the same. What will be the ratio of
- their momenta
- their kinetic energies?
Find the ratio of the de Broglie wavelengths of an electron and a proton when both are moving with the (a) same speed, (b) the same kinetic energy, and (c) the same momentum. State which of the two will have a longer wavelength in each case.
According to De-Broglie, the waves are associated with ______
The momentum of a photon of energy 1 MeV in kg m/s will be ______
According to de-Broglie hypothesis, the wavelength associated with moving electron of mass 'm' is 'λe'· Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is 'λp'. If the energy (E) of electron and photon is same then relation between 'λe' and 'λp' is ______.
An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is ( c being velocity of light) ______.
If the radius of the circular path and frequency of revolution of a particle of mass m are doubled, then the change in its kinetic energy will be (Ei and Ef are the initial and final kinetic energies of the particle respectively.)
How much energy is imparted to an electron so that its de-Broglie wavelength reduces from 10-10 m to 0.5 × 10-10 m? (E =energy of electron)
If '`lambda_1`' and '`lambda_2`' are de-Broglie wavelengths for electrons in first and second Bohr orbits in hydrogen atom, then the ratio '`lambda_2`' to '`lambda_1`' is (E1 = -13.6 eV) ____________.
If the kinetic energy of a particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is ____________.
If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with the electrons change?
According to de-Broglie hypothesis, the ratio of wavelength of an electron and that of photon having same energy 'E' is (m = mass of electron, c = velocity of light) ____________.
Explain de-Broglie wavelength.
Obtain an expression for de-Broglie wavelength of wave associated with material particles. The photoelectric work function for metal is 4.2 eV. Find the threshold wavelength.
A proton, a neutron, an electron and an α-particle have same energy. λp, λn, λe and λα are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following :
The energy of an electron having de-Broglie wavelength `λ` is ______.
(h = Plank's constant, m = mass of electron)
An electron of mass m has de-Broglie wavelength λ when accelerated through potential difference V. When proton of mass M, is accelerated through potential difference 9V, the de-Broglie wavelength associated with it will be ______. (Assume that wavelength is determined at low voltage)
An electron is accelerated through a potential difference of 100 volts. Calculate de-Broglie wavelength in nm.
Calculate the de Broglie wavelength associated with an electron moving with a speed of `5 xx 10^6` m/s. `(m_e = 9.1 xx 10^(-31)kg)`
A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as ______.
A photon and an electron have an equal energy ‘E’. The ratio of wavelength ‘λp’ of photon to that of electron ‘λe’ is proportional to ______.
If the potential difference used to accelerate electrons is tripled, by what factor does the de-Broglie wavelength associated with electrons change?
