हिंदी

An electron, a proton, an α-particle, and a hydrogen atom are moving with the same kinetic energy. The associated de Broglie wavelength will be longest for ______. - Physics

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प्रश्न

An electron, a proton, an α-particle, and a hydrogen atom are moving with the same kinetic energy. The associated de Broglie wavelength will be longest for ______.

विकल्प

  • Electron

  • Proton

  • α-particle

  • Hydrogen atom

MCQ
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उत्तर

An electron, a proton, an α-particle, and a hydrogen atom are moving with the same kinetic energy. The associated de Broglie wavelength will be longest for electron.

Explanation:

The equation which relates Kinetic energy and De Broglie wavelength is  `lambda = h/sqrt(2mE)`

  • According to the given condition, kinetic energy E is the same for all the given particles.
  • So, the value of the de Broglie wavelength depends on the mass of the particle. If the mass of the particle is more, then de Broglie's wavelength is lower, and vice versa.
  • Among the given particles, the electron has the lowest mass in the order of 9.1 × 10−31 kg.
  • Therefore, the electron has the longest de Broglie wavelength.
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अध्याय 14: Dual Nature of Radiation and Matter - Exercises [पृष्ठ ३२२]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 14 Dual Nature of Radiation and Matter
Exercises | Q 1.3 | पृष्ठ ३२२

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