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Explain de-Broglie wavelength. - Physics

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प्रश्न

Explain de-Broglie wavelength.

संक्षेप में उत्तर
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उत्तर

The wavelength that is associated with an object in relation to its momentum and mass is known as the de-Broglie wavelength.

de-Broglie equated the energy equation of Plank (wave nature) and Einstein (particle nature) such that,

E = hv   (Plank energy relation)

E = mc2   (Einsteins mass-energy relation)

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De Broglie Hypothesis
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2021-2022 (March) Set 1

संबंधित प्रश्न

An electron, a proton, an α-particle, and a hydrogen atom are moving with the same kinetic energy. The associated de Broglie wavelength will be longest for ______.


State the importance of Davisson and Germer experiment.


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Find the ratio of the de Broglie wavelengths of an electron and a proton when both are moving with the (a) same speed, (b) the same kinetic energy, and (c) the same momentum. State which of the two will have a longer wavelength in each case.


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Explain De Broglie’s Hypothesis.


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If the radius of the innermost Bohr orbit is 0.53 Å, the radius of the 4th orbit is ______


According to de-Broglie hypothesis, the wavelength associated with moving electron of mass 'm' is 'λe'· Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is  'λp'. If the energy (E) of electron and photon is same then relation between 'λe' and 'λp' is ______.


An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is ( c being velocity of light) ______.


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A particle of charge q, mass m and energy E has de-Broglie wavelength `lambda.` For a particle of charge 2q, mass 2m and energy 2E, the de-Broglie wavelength is ____________.


How much energy is imparted to an electron so that its de-Broglie wavelength reduces from 10-10 m to 0.5 × 10-10 m? (E =energy of electron)


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If the kinetic energy of a particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is ____________.


Graph shows the variation of de-Broglie wavelength `(lambda)` versus `1/sqrt"V"`, where 'V' is the accelerating potential for four particles carrying same charge but of masses m1 , m2, m3, m4. Which particle has a smaller mass?


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A proton, a neutron, an electron and an α-particle have same energy. λp, λn, λe and λα are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following :


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