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Karnataka Board PUCPUC Science Class 11

Calculate the Amount of Heat Radiated per Second by a Body of Surface Area 12 Cm2 Kept in Thermal Equilibrium in a Room at Temperature 20°C. the Emissivity of the Surface = 0.80 and - Physics

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Question

A spherical ball of surface area 20 cm2 absorbs any radiation that falls on it. It is suspended in a closed box maintained at 57°C. (a) Find the amount of radiation falling on the ball per second. (b) Find the net rate of heat flow to or from the ball at an instant when its temperature is 200°C. Stefan constant = 6.0 × 10−8 W m−2 K−4.

Sum
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Solution

(a)
Area of the ball, A = 20 × 10−4 m2

Temperature of the ball, T = 57°C = 57 + 273 = 330 K

Amount of heat radiated per second = AσT4

   = 20 × 10−4 × 6 × 10−8 × (330)4

   = 1.42 J
(b)
Net rate of heat flow from the ball when its

emperature is 200 °C is given by

eAσ (T14 - T24)

= 20 × 10-4 × 6 × 10-8 × 1 ((473)4 - (330)4  [∴ e = 1]
= 4.58 W

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Thermal Expansion of Solids
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Chapter 6: Heat Transfer - Exercises [Page 101]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 6 Heat Transfer
Exercises | Q 43 | Page 101

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