English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Between the primary and secondary rainbows, there is a dark band known as Alexandar’s dark band. This is because ______. light scattered into this region interfere destructively. there is no light - Physics

Advertisements
Advertisements

Question

Between the primary and secondary rainbows, there is a dark band known as Alexandar’s dark band. This is because ______.

  1. light scattered into this region interfere destructively.
  2. there is no light scattered into this region.
  3. light is absorbed in this region.
  4. angle made at the eye by the scattered rays with respect to the incident light of the sun lies between approximately 42° and 50°.

Options

  • a and c

  • a and d

  • b and d

  • c and d

MCQ
Fill in the Blanks
Advertisements

Solution

a and d

Explanation:

The Alexandar’s dark band lies between the primary and secondary rainbows, formed due to light scattered into this region interfere destructively. The primary rainbows subtend an angle of nearly 41° to 42° at the observer’s eye, whereas secondary rainbows subtend an angle of nearly 51° to 54° at the observer’s eye w.r.t. incident light ray.

Hence, the scattered rays with respect to the incident light of the sun lie between approximately 42° and 50°.

shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Ray Optics And Optical Instruments - MCQ I [Page 57]

APPEARS IN

NCERT Exemplar Physics [English] Class 12
Chapter 9 Ray Optics And Optical Instruments
MCQ I | Q 9.14 | Page 57

RELATED QUESTIONS

Why does unpolarised light from a source show a variation in intensity when viewed through a polaroid which is rotated?


What is linearly polarized light? 


Describe briefly using a diagram how sunlight is polarised ?


The image formed by a concave mirror


A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side on its principal axis, the intensity of light


A point source S is placed midway between two converging mirrors having equal focal length f as shown in figure. Find the values of d for which only one image is formed.


A converging mirror M1, a point source S and a diverging mirror M2 are arranged as shown in figure. The source is placed at a distance of 30 cm from M1. The focal length of each of the mirrors is 20 cm. Consider only the images formed by a maximum of two reflections. It is found that one image is formed on the source itself. (a) Find the distance between the two mirrors. (b) Find the location of the image formed by the single reflection from M2.


k transparent slabs are arranged one over another. The refractive indices of the slabs are μ1, μ2, μ3, ... μk and the thicknesses are t1 t2t3, ... tk. An object is seen through this combination with nearly perpendicular light. Find the equivalent refractive index of the system which will allow the image to be formed at the same place.


Light is incident from glass (μ = 1.50) to water (μ = 1.33). Find the range of the angle of deviation for which there are two angles of incidence.


A biconvex thick lens is constructed with glass (μ = 1.50). Each of the surfaces has a radius of 10 cm and the thickness at the middle is 5 cm. Locate the image of an object placed far away from the lens.


One end of a cylindrical glass rod (μ = 1.5) of radius 1.0 cm is rounded in the shape of a hemisphere. The rod is immersed in water (μ = 4/3) and an object is placed in the water along the axis of the rod at a distance of 8.0 cm from the rounded edge. Locate the image of the object.


Fill in the blank and rewrite the completed statement:

Very fine particles mainly scatter ______ light.


Answer the following question in detail.

State the conditions under which a rainbow can be seen.


Answer the following question in detail.

Explain the formation of a secondary rainbow. For which angular range with the horizontal is it visible?


Answer the following question in detail.

Is it possible to see primary and secondary rainbow simultaneously? Under what conditions?


Pick the wrong answer in the context with rainbow.


Case study: Mirage in deserts

To a distant observer, the light appears to be coming from somewhere below the ground. The observer naturally assumes that light is being reflected from the ground, say, by a pool of water near the tall object.

Such inverted images of distant tall objects cause an optical illusion to the observer. This phenomenon is called mirage. This type of mirage is especially common in hot deserts.

Based on the above facts, answer the following question :

In an optical fibre, if n1 and n2 are the refractive indices of the core and cladding, then which among the following, would be a correct equation? 


Case study: Mirage in deserts 

To a distant observer, the light appears to be coming from somewhere below the ground. The observer naturally assumes that light is being reflected from the ground, say, by a pool of water near the tall object.

Such inverted images of distant tall objects cause an optical illusion to the observer. This phenomenon is called mirage. This type of mirage is especially common in hot deserts.

Based on the above facts, answer the following question:

A diamond is immersed in such a liquid which has its refractive index with respect to air as greater than the refractive index of water with respect to air. Then the critical angle of diamond-liquid interface as compared to critical angle of diamond-water interface will


A short pulse of white light is incident from air to a glass slab at normal incidence. After travelling through the slab, the first colour to emerge is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×