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Question
Assume the dipole model for earth’s magnetic field B which is given by BV = vertical component of magnetic field = `mu_0/(4pi) (2m cos theta)/r^3` BH = Horizontal component of magnetic field = `mu_0/(4pi) (sin theta m)/r^3` θ = 90° – lattitude as measured from magnetic equator. Find loci of points for which (i) |B| is minimum; (ii) dip angle is zero and (iii) dip angle is ± 45°.
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Solution
(i) We know from the figure.
`B^2 + B_V^2 + B_H^2`
= `[mu_0/(4pi) (2m cos theta)/r^3]^2 + [mu_0/(4pi) (m sin theta)/r^3]^2`
Substituting the value of BV and BH from question
= `[mu_0/(4pi)]^2 m^2/r^3 [4cos^2 theta + sin^2 theta]`
`B^2 = (mu_0/(4pi)) xx m^2/r^3 [3 cos^2 theta + 1]`
`B = mu_0/(4pi) m/r^3 [3 cos^2 theta + 1]^(1/2)` ......(i)
From equation (i), the value of B will be minimum when `[3cos^2 theta + 1]^(1/2)` is minimum which will be at `theta= pi/2`. So magnetic equator lies ar `theta = pi/2`, i.e., from magnetic dipole axis `theta = pi/2` for magnetic equator.
(ii) For angle of dip δ
tan δ = `B_r/B_H = (mu_0/(4pi) (2m cos theta)/r^3)/(mu_0/(4pi) (m sin theta)/r^3)`
tan δ = 2 cot θ
For δ = 0, cot θ = 0, θ = `pi/2`
So angle of dip will lie at magnetic equator.
(iii) tan δ = `B_V/B_H` = angle of dip δ = ± 45°
⇒ `B_V/B_H` = tan ± 45°
⇒ `B_V/B_H` = tan 45°
`B_V/B_H` = 1 or BV = BH
δ = ± 45°
tan ± 45° = 2 cos θ .....[∵ tan δ = 2 cot θ]
cot θ = `1/2` or tan θ = 2
θ = tan–12 is the locus of points where the angle of dip δ = ± 45°.
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