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Arrange the following ratios in descending order of magnitude: (6 : 7), (13 : 14), (19 : 21) and (23 : 28)

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Question

Arrange the following ratios in descending order of magnitude: 

(6 : 7), (13 : 14), (19 : 21) and (23 : 28)

Sum
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Solution

L.C.M. of denominators 7, 14, 21 and 28 is 84.

$$\frac{6}{7} = \frac{72}{84}$$

$$\frac{13}{14} = \frac{78}{84}$$

$$\frac{19}{21} = \frac{76}{84}$$

$$\frac{23}{28} = \frac{69}{84}$$

Comparing numerators in descending order: $$78 > 76 > 72 > 69$$.

Descending order: $$(13 : 14), (19 : 21), (6 : 7), (23 : 28)$$.

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Chapter 7: Ratio and Proportion - EXERCISE 7A [Page 95]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 7 Ratio and Proportion
EXERCISE 7A | Q 38. (ii) | Page 95
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