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Arrange the following ratios in descending order of magnitude: (5 : 6), (8 : 9), (13 : 18) and (19 : 24)

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Question

Arrange the following ratios in descending order of magnitude: 

(5 : 6), (8 : 9), (13 : 18) and (19 : 24)

Sum
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Solution

L.C.M. of denominators 6, 9, 18 and 24 is 72.

$$\frac{5}{6} = \frac{60}{72}$$

$$\frac{8}{9} = \frac{64}{72}$$

$$\frac{13}{18} = \frac{52}{72}$$

$$\frac{19}{24} = \frac{57}{72}$$

Comparing numerators in descending order: $$64 > 60 > 57 > 52$$.

Descending order: $$(8 : 9), (5 : 6), (19 : 24), (13 : 18)$$.

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Chapter 7: Ratio and Proportion - EXERCISE 7A [Page 95]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 7 Ratio and Proportion
EXERCISE 7A | Q 38. (i) | Page 95
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