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Question
Answer the following:
Find f(x) if g(x) = `1 + sqrt(x)` and f[g(x)] = `3 + 2sqrt(x) + x`
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Solution
g(x) = `1 + sqrt(x)`
f(g(x)) = `3 + 2 sqrt(x) + x (sqrt(x) + 1)^2 + 2`
`"f"(sqrt(x) + 1) - (sqrt(x) + 1)^2 + 2`
∴ f(x) = x2 + 2
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