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Karnataka Board PUCPUC Science 2nd PUC Class 12

Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions?

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Question

Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions?

Numerical
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Solution

The formula Ni0.98O1.00 indicates that 98 Ni atoms are associated with 100 O atoms. Suppose,

Number of Ni atoms present as Ni2+ = x

∴ Number of Ni atoms present as Ni3+ = 98 − x

Since nickel oxide is electrically neutral, the total charge present on x Ni2+ ions and (98 − x) Ni3+ ions should be equal to the total charge present on 100 O2− ions. Therefore, we have

(x × 2) + (98 − x) × 3 = 100 × 2

or 2x + 294 − 3x = 200

or x = 94

∴ Fraction of Ni present as Ni2+ = `94/98 xx 100`

= 95.9

= 96%

and fraction of Ni present as Ni3+ = `(98 - 94)/98 xx 100`

= 4.08

= 4%

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