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Questions
Give a reason for the following:
Cu+2 salts are paramagnetic, while Cu+ salts are diamagnetic.
Cu(II) is paramagnetic but Cu(I) is diamagnetic. Give reason (At. no. of Cu = 29).
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Solution 1
The electronic configurations of Cu2+ and Cu+ are [Ar] 3d9 4s0 and [Ar] 3d10 4s0, respectively. Cu2+ has one unpaired electron, making it paramagnetic, whereas Cu+ has no unpaired electrons, making it diamagnetic.
Solution 2
- Atomic number of Cu = 29, electronic configuration is [Ar] 3d10 4s1.
- Cu(I) ion has oxidation state +1, so it loses one 4s electron. Its configuration becomes 3d10 (fully filled d-orbitals).
- Since all electrons in Cu(I) are paired in the 3d10 configuration, the Cu(I) ion is diamagnetic (no unpaired electrons).
- Cu(II) ion has oxidation state +2, so it loses one 4s electron and one 3d electron. Configuration becomes 3d9.
- With one unpaired electron in the 3d9 configuration, the Cu(II) ion is paramagnetic (has unpaired electrons).
Therefore, Cu(II) ion is paramagnetic due to the presence of one unpaired electron, while Cu(I) is diamagnetic because all electrons are paired.
Notes
Students can refer to the provided solutions based on their preferred marks.
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