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Question
An urn contains 10 red and 8 white balls. One ball is drawn at random. Find the probability that the ball drawn is white.
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Solution
\[\text{ Number of red balls } = 10\]
\[\text{ Number of white balls }= 8\]
\[\text{ Total number of balls in the urn } = 10 + 8 = 18\]
\[\text{ Therefore, the total number of cases is 18 and the number of favourable cases is 8 }. \]
\[ \therefore P\left( \text{ The ball drawn is white }\right) = \frac{\text{ Number of favourable cases }}{\text{ Total number of cases }} = \frac{8}{18} = \frac{4}{9}\]
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