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Question
An induced current of 2.5 mA flows through a single conductor of resistance 100 Ω. Find out the rate at which the magnetic flux is cut by the conductor.
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Solution
Given data:
Induced current i = 2.5 mA
i= 2.5 × 10-3 A
Resistance R = 100Ω
ε = `("d"phi_"B")/"dt"`
where ε = iR
`therefore ("d"phi_"B")/"dt"` = iR = 2.5 × 10-3 × 100
= 250 × 10-3
= 250 mWbs-1
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