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An induced current of 2.5 mA flows through a single conductor of resistance 100 Ω. Find out the rate at which the magnetic flux is cut by the conductor.

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प्रश्न

An induced current of 2.5 mA flows through a single conductor of resistance 100 Ω. Find out the rate at which the magnetic flux is cut by the conductor.

संख्यात्मक
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उत्तर

Given data:

Induced current i = 2.5 mA

i= 2.5 × 10-3 A

Resistance R = 100Ω

ε = `("d"phi_"B")/"dt"`

where ε = iR

`therefore ("d"phi_"B")/"dt"` = iR = 2.5 × 10-3 × 100

= 250 × 10-3

= 250 mWbs-1

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अध्याय 4: Electromagnetic Induction And Alternating Current - Evaluation [पृष्ठ २६२]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Electromagnetic Induction And Alternating Current
Evaluation | Q IV. 6. | पृष्ठ २६२

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A solenoid of length 1.5 m and 4 cm in diameter possesses 10 turns per metre. A current of 5 A is flowing through it. The magnetic induction at a point inside the solenoid along the axis is ............................. .

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  1. π  × 10-5 T
  2. 2π × 10-5 T
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