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A coil of 200 turns carries a current of 4 A. If the magnetic flux through the coil is 6 x 10-5 Wb, find the magnetic energy stored in the medium surrounding the coil.

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प्रश्न

A coil of 200 turns carries a current of 4 A. If the magnetic flux through the coil is 6 x 10-5 Wb, find the magnetic energy stored in the medium surrounding the coil.

संख्यात्मक
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उत्तर

Given data:

N = 200 turns

i = 4A

ΦB = 6 × 10-5 Wb

Magnetic energy UB = ?

`"U"_"B" = 1/2 "Li"^2`

`therefore "U"_"B" = 1/2 ("N"phi_"B")/"i"  "i"^2`

`"U"_"B" = 1/2 "N"phi_"B" "i"`

`= 1/2 xx 200 xx 6 xx 10 xx 4`

UB = 24 × 10-5 J

UB = 0.024 J

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अध्याय 4: Electromagnetic Induction And Alternating Current - Evaluation [पृष्ठ २६२]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Electromagnetic Induction And Alternating Current
Evaluation | Q IV. 10. | पृष्ठ २६२

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