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Question
An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1.20 A/s. What is the mutual inductance (M) of the two coils?
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Solution
Given:
e = 96 mV = 96 × 10-3 V,
`"dI"/"dt"` = 1.20 A/s
To find: Mutual Inductance (M)
Formula: M = `|"e"|/|"dI""/""dt"|`
Calculation:
From formula
M = `(96 xx 10^-3)/1.2`
`= 80 xx 10^-3`
= 80 mH
Mutual Inductance of the two coils is 80 mH.
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