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A Coil of Self-inductance 2.5h and Resistance 20ω is Connected to a Battery of Emf 120v Having the Internal Resistance of 5 N. Find: 1) The Time Constant of the Circuit. 2) The Current in the Circuit in Steady State - Physics (Theory)

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Question

A coil of self-inductance 2.5H and resistance 20Ω is connected to a battery of emf 120V having the internal resistance of 5 n. Find:

1) The time constant of the circuit.

2) The current in the circuit in steady state

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Solution

Given

l = 2.5h

R = 20Ω

E = 120V

r = 5Ω

1) Tme constant , `t = L/R = 2.5/20 = 1/8 = 0.125 s`

2) Current, `I = E/(R  + r) =- 120/25 = 4.8 A`                                                    

 

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2014-2015 (March)

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