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Question
An emf of 2V is induced in a coil when the current in it is changed from 0A to 10A in 0·40 sec. Find the coefficient of self-inductance of the coil.
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Solution
`|L| = e xx (dt)/(dl)`
`L= 2 xx (0.4)/10 = 0.8/10 = 0.08 H`
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