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An electrical appliance having a resistance of 200 Ω is operated at 220 V. Calculate the energy consumed by the appliance in 5 minutes in kWh.

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Question

An electrical appliance having a resistance of 200 Ω is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes in kWh.

Sum
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Solution

Given resistance, R = 200 Ω

Voltage, V = 200 V

time, t = 5 min

= 5 × 60 sec

= 300 sec

As, Energy, E = `("V"^2"t")/"R"`

In kWh 

As 1 kWh = 3.6 × 106 J

1 J = `1/(3.6 xx 10^6)` kWh

60000 J = `60000/(3.6 xx 10^6)` = 0.0167 kWh

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Chapter 8: Current Electricity - EXERCISE - 8(C) [Page 212]

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Selina Concise Physics [English] Class 10 ICSE
Chapter 8 Current Electricity
EXERCISE - 8(C) | Q 8. (ii) | Page 212

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