Question

An effort of 8 kgf is applied on a machine through a distance of 50 cm, when a load of 100 kgf moves through a distance of 3 cm. Calculate

1. velocity ratio
2. mechanical advantage
3. % age efficiency of the machine.

Answer 1

\[ \text{(a) Velocity ratio} = \frac{\text{Distance through which the effort moves}}{\text{Distance through which the load moves}} = \frac{50\ \mathrm{cm}}{3\ \mathrm{cm}} = {16.67} \]

\[ \text{(b) Mech. Adv.} = \frac{\text{Load}}{\text{Effort}} = \frac{100\ \mathrm{kgf}}{8\ \mathrm{kgf}} = {12.5} \]

\[ \text{(c) \% age efficiency} = \frac{\mathrm{MA}}{\mathrm{VR}} \times 100 = \frac{12.5}{16.67} \times 100 = {75\%} \]