Question

A machine displaces a load of 125 kgf through a distance 0.30 m, when an effort of 12.5 kgf acts through a distance of 4.0 m. Calculate the

1. velocity ratio
2. mechanical advantage
3. % age efficiency of the machine.

Answer 1

\[ \text{(a) Velocity ratio} = \frac{\text{Distance through which the effort moves}}{\text{Distance through which the load moves}} = \frac{4.0\ \text{m}}{0.30\ \text{m}} = 13.33 \] \[ \text{(b) Mech. Adv.} = \frac{\text{Load}}{\text{Effort}} = \frac{125\ \text{kgf}}{12.5\ \text{kgf}} = 10 \] \[ \text{(c) \% age efficiency} = \frac{\text{MA}}{\text{VR}} \times 100 = \frac{10}{13.33} \times 100 = 75\% \]