Advertisements
Advertisements
Question
An alloy consists of `27(1)/(2)` kg of copper and `2(3)/(4)` kg of tin. Find the ratio by weight of tin to the alloy.
Advertisements
Solution
Copper = `27(1)/(2) "kg" = (55)/(2)"kg"`,
Tin = `2(3)/(4)"kg" = (11)/(4)"kg"`
Total alloy
= `(55)/(2) + (11)/(4)`
= `(110 + 11)/(4)`
= `(121)/(4)"kg"`
Now Ratio between tin and alloy
= `(11)/(4)"kg" : (121)/(4)"kg"`
= 11 : 121
= 1 : 11
APPEARS IN
RELATED QUESTIONS
If Chameli had Rs 600 left after spending 75% of her money, how much did she have in the beginning?
In a mixture of 126 kg of milk and water, milk and water are in ratio 5 : 2. How much water must be added to the mixture to make this ratio 3 : 2?
Find the compounded ratio of the following:
(m-n):(m+n), (m+n)2 : (m2+n2) and (m4 - n4): (m2-n2) 2
Express the following ratios in its simplest form :
200:250
The hypotenuse of a right angled triangle is 3`sqrt(5)`. If the smaller side is tripled and the larger side is doubled, the new hypotenuse will be 15 cm. Find the length of each side.
Show that 2, 12 and 72 are in continued proportion.
Divide Rs 1575 between Kamal and Madhu in the ratio 7 : 2.
`3/8 = 15/40`
Samira sells newspapers at Janpath crossing daily. On a particular day, she had 312 newspapers out of which 216 are in English and remaining in Hindi. Find the ratio of the number of Hindi newspapers to the total number of newspapers.
Find the ratio of the following:
98 to 63
