Advertisements
Advertisements
प्रश्न
An alloy consists of `27(1)/(2)` kg of copper and `2(3)/(4)` kg of tin. Find the ratio by weight of tin to the alloy.
Advertisements
उत्तर
Copper = `27(1)/(2) "kg" = (55)/(2)"kg"`,
Tin = `2(3)/(4)"kg" = (11)/(4)"kg"`
Total alloy
= `(55)/(2) + (11)/(4)`
= `(110 + 11)/(4)`
= `(121)/(4)"kg"`
Now Ratio between tin and alloy
= `(11)/(4)"kg" : (121)/(4)"kg"`
= 11 : 121
= 1 : 11
APPEARS IN
संबंधित प्रश्न
Find the ratio of the following in the simplest fcrm:
x2 + 4x +4 and x2 - x - 6
Two numbers are in the ratio 7 : 10. If 8 is added to each number, the ratio becomes 3 : 4. Find the nLimbers.
Solve for x: `(3x^2 + 5x + 18)/(5x^2 + 6x + 12) = (3x + 5)/(5x - 6)`.
Divide 64 cm long string into two parts in the ratio 5 : 3.
Reduce the following ratio to their lowest term:
5 kg 500 gm : 2 kg 750 gm
Find the sub-triplicate ratio of `(1)/(8) : (1)/(125)`
Write the following ratio in the simplest form:
4 kg : 2 kg 500 g
Fill in the place holder:
In the ratio 7 : 11, which term is called the consequent?
