Question

Add:

2p⁴ – 3p³ + p² – 5p + 7, –3p⁴ – 7p³ – 3p² – p – 12

Answer 1

We have,

(2p⁴ – 3p³ + p² – 5p + 7) + (–3p⁴ – 7p³ – 3p² – p – 12)

= 2p⁴ – 3p³ + p² – 5p + 7 – 3p⁴ – 7p³ – 3p² – p – 12

= (2p⁴ – 3p⁴) + (–3p³ – 7p³) + (p² – 3p²) + (–5p – p) + (7 – 12)  ...[Grouping like terms]

= – p⁴ + (–10p³) + (–2p²) + (–6p) + (–5)

= – p⁴ – 10p³ – 2p² – 6p – 5