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प्रश्न
Add:
2p4 – 3p3 + p2 – 5p + 7, –3p4 – 7p3 – 3p2 – p – 12
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उत्तर
We have,
(2p4 – 3p3 + p2 – 5p + 7) + (–3p4 – 7p3 – 3p2 – p – 12)
= 2p4 – 3p3 + p2 – 5p + 7 – 3p4 – 7p3 – 3p2 – p – 12
= (2p4 – 3p4) + (–3p3 – 7p3) + (p2 – 3p2) + (–5p – p) + (7 – 12) ...[Grouping like terms]
= – p4 + (–10p3) + (–2p2) + (–6p) + (–5)
= – p4 – 10p3 – 2p2 – 6p – 5
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संबंधित प्रश्न
Add the following:
l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl
Simplify combining like terms: 5x2y − 5x2 + 3y x2 − 3y2 + x2 − y2 + 8xy2 −3y2
Add: ab - 4a, 4b - ab, 4a - 4b
What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
Add the following algebraic expression:
3a2b, − 4a2b, 9a2b
Subtract:
2a − b from 3a − 5b
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
Add:
−3y2 + 10y − 16; 7y2 + 8
Add: 8x, 3x
