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प्रश्न
Add:
2p4 – 3p3 + p2 – 5p + 7, –3p4 – 7p3 – 3p2 – p – 12
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उत्तर
We have,
(2p4 – 3p3 + p2 – 5p + 7) + (–3p4 – 7p3 – 3p2 – p – 12)
= 2p4 – 3p3 + p2 – 5p + 7 – 3p4 – 7p3 – 3p2 – p – 12
= (2p4 – 3p4) + (–3p3 – 7p3) + (p2 – 3p2) + (–5p – p) + (7 – 12) ...[Grouping like terms]
= – p4 + (–10p3) + (–2p2) + (–6p) + (–5)
= – p4 – 10p3 – 2p2 – 6p – 5
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संबंधित प्रश्न
Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz.
Simplify combining like terms: 21b − 32 + 7b − 20b
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Add: ab - 4a, 4b - ab, 4a - 4b
Subtract: 5a2 - 7ab + 5b2 from 3ab - 2a2 -2b2
What should be subtracted from 2a + 8b + 10 to get - 3a + 7b + 16?
Add the following algebraic expression:
\[\frac{3}{2}a - \frac{5}{4}b + \frac{2}{5}c, \frac{2}{3}a - \frac{7}{2}b + \frac{7}{2}c, \frac{5}{3}a + \frac{5}{2}b - \frac{5}{4}c\]
Add:
17a2b2 + 16c; 28c − 28a2b2
Simplify: n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
What should be added to 3pq + 5p2q2 + p3 to get p3 + 2p2q2 + 4pq?
