Advertisements
Advertisements
प्रश्न
Add the following algebraic expression:
\[\frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x, - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
Advertisements
उत्तर
To add, we proceed as follows:
\[\left( \frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x \right) + \left( - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy \right)\]
\[ = \frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
\[ = \frac{11}{2}xy - \frac{13}{7}xy + \frac{12}{5}y - \frac{11}{2}y + \frac{13}{7}x - \frac{12}{5}x ( \text { Collecting like terms })\]
\[ = \frac{51}{14}xy - \frac{31}{10}y - \frac{19}{35}x (\text { Combining like terms })\]
APPEARS IN
संबंधित प्रश्न
Simplify combining like terms: - z2 + 13z2 − 5z + 7z3 − 15z
What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?
From the sum of 4 + 3x and 5 - 4x + 2x2, subtract the sum of 3x2 - 5x and -x2 + 2x + 5.
Subtract:
− 5xy from 12xy
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
Add:
13x2 − 12y2; 6x2 − 8y2
Add the following expressions:
ab + bc + ca and – bc – ca – ab
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
What should be added to 3pq + 5p2q2 + p3 to get p3 + 2p2q2 + 4pq?
