Advertisements
Advertisements
प्रश्न
Subtract:
2x3 − 4x2 + 3x + 5 from 4x3 + x2 + x + 6
Advertisements
उत्तर
\[ \left( 4 x^3 + x^2 + x + 6 \right) - \left( 2 x^3 - 4 x^2 + 3x + 5 \right)\]
\[ = 4 x^3 + x^2 + x + 6 - 2 x^3 + 4 x^2 - 3x - 5\]
\[ = 4 x^3 - 2 x^3 + x^2 + 4 x^2 + x - 3x + 6 - 5 \text { (Collecting like terms })\]
\[ = 2 x^3 + 5 x^2 - 2x + 1 (\text { Combining like terms })\]
संबंधित प्रश्न
Add the following:
l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl
Subtract: 6xy from − 12xy
What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?
Add the following algebraic expression:
3a2b, − 4a2b, 9a2b
Add the following algebraic expression: \[\frac{7}{2} x^3 - \frac{1}{2} x^2 + \frac{5}{3}, \frac{3}{2} x^3 + \frac{7}{4} x^2 - x + \frac{1}{3}, \frac{3}{2} x^2 - \frac{5}{2}x - 2\]
Subtract the sum of 2x − x2 + 5 and − 4x − 3 + 7x2 from 5.
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
Add: 7mn, 5mn
Find the expression to be added with 5a – 3b – 2c to get a – 4b – 2c?
Add the following expressions:
t – t2 – t3 – 14; 15t3 + 13 + 9t – 8t2; 12t2 – 19 – 24t and 4t – 9t2 + 19t3
