Advertisements
Advertisements
प्रश्न
Add:
5x2 – 3xy + 4y2 – 9, 7y2 + 5xy – 2x2 + 13
Advertisements
उत्तर
We have,
(5x2 – 3xy + 4y2 – 9) + (7y2 + 5xy – 2x2 + 13)
= 5x2 – 3xy + 4y2 – 9 + 7y2 + 5xy – 2x2 + 13
= (5x2 – 2x2) + (–3xy + 5xy) + (4y2 + 7y2) + (–9 + 13) ...[Grouping like terms]
= 3x2 + 2xy + 11y2 + 4
APPEARS IN
संबंधित प्रश्न
Add the following:
2p2q2 − 3pq + 4, 5 + 7pq − 3p2q2
Subtract: 6xy from − 12xy
Subtract: 5a2 - 7ab + 5b2 from 3ab - 2a2 -2b2
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
Add:
13x2 − 12y2; 6x2 − 8y2
Multiply the following:
(ab + c), (ab + c)
The number of scarfs of length half metre that can be made from y metres of cloth is ______.
Add the following expressions:
`5/8p^4 + 2p^2 + 5/8; 1/8 - 17p + 9/8p^2` and `p^5 - p^3 + 7`
How much is y4 – 12y2 + y + 14 greater than 17y3 + 34y2 – 51y + 68?
