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प्रश्न
Add:
xy2z2 + 3x2y2z – 4x2yz2, – 9x2y2z + 3xy2z2 + x2yz2
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उत्तर
We have,
(xy2z2 + 3x2y2z – 4x2yz2) + (– 9x2y2z + 3xy2z2 + x2yz2)
= xy2z2 + 3x2y2z – 4x2yz2 – 9x2y2z + 3xy2z2 + x2yz2
= (xy2z2 + 3xy2z2) + (3x2y2z – 9x2y2z) + (– 4x2yz2 + x2yz2) ...[Grouping like terms]
= 4xy2z2 + (– 6x2y2z) + (–3x2yz2)
= 4xy2z2 – 6x2y2z – 3x2yz2
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