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Question
Add:
3a(a – b + c), 2b(a – b + c)
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Solution
We have,
3a(a – b + c) + 2b(a – b + c)
= (3a2 – 3ab + 3ac) + (2ab – 2b2 + 2bc)
= 3a2 – 3ab + 2ab + 3ac + 2bc – 2b2 ...[Grouping like terms]
= 3a2 – ab + 3ac + 2bc – 2b2
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