Advertisements
Advertisements
Question
AC is a tangent to the given circle which touches the circle at point B . If angle EBC = 45°; angle EDB is equal to:

Options
45°
90°
125°
135°
MCQ
Advertisements
Solution
45°
Explanation:
From figure,
⇒ ∠ABE + ∠EBC = 180° [Linear pair]
⇒ ∠ABE + 45° = 180°
⇒ ∠ABE = 180° − 45° = 135°
We know that,
The angle between a tangent and a chord through the point of contact is equal to an angle in the alternate segment.
⇒ ∠EDB = ∠ABE = 135°
shaalaa.com
Is there an error in this question or solution?
