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Question
If angle PAC : angle PCA = 5: 4 ; angle P is ______.

Options
40°
60°
105°
45°
MCQ
Fill in the Blanks
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Solution
If angle PAC : angle PCA = 5: 4 ; angle P is 45°.
Explanation:
We know that,
Sum of co-interior angles in a trapezium is 180°.
In trapezium ABDC,
⇒ ∠B + ∠BAC = 180°
⇒ 60° + ∠BAC = 180°
⇒ ∠BAC = 180° − 60° = 120°
From figure,
⇒ ∠PAC + ∠BAC = 180°
⇒ ∠PAC + 120° = 180°
⇒ ∠PAC = 180° − 120° = 60°
Given,
⇒ ∠PAC : ∠PCA = 4 : 5
⇒ `(∠PAC)/(∠PCA) = 4/5`
⇒ `(60°)/(∠PCA) = 4/5`
⇒ `∠PCA = (60°×5)/4`
⇒ ∠PCA = `(300°)/4` = 75°
In △PCA,
By angle sum property of triangle,
⇒ ∠APC + ∠PAC + ∠PCA = 180°
⇒ ∠APC + 60° + 75° = 180°
⇒ ∠APC + 135° = 180°
⇒ ∠APC = 180° − 135° = 45°
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