Question

AC is a tangent to the given circle which touches the circle at point B . If angle EBC = 45°; angle EDB is equal to:

विकल्प

• 45°

• 90°

• 125°

• 135°

Answer 1

45°

Explanation:

From figure,

⇒ ∠ABE + ∠EBC = 180° [Linear pair]

⇒ ∠ABE + 45° = 180°

⇒ ∠ABE = 180° − 45° = 135°

We know that,

The angle between a tangent and a chord through the point of contact is equal to an angle in the alternate segment.

⇒ ∠EDB = ∠ABE = 135°