Advertisements
Advertisements
Question
ABCD is a rhombus. If ∠BCA = 35°. find ∠ADC.
Advertisements
Solution
Given : Rhombus ABCD in which ∠BCA = 35°
To find : ∠ADC
Proof : AD || BC
∠DAC = ∠BCA (Alternate ∠s)
But ∠BCA = 35° (Given)
∠DAC = 35°
But ∠DAC = ∠ACD ( AD = CD) & ∠DAC +∠ACD + ∠ADC = 180°
35°+ 35° + ∠ADC = 180°
∠ADC = 180° – 70° = 110°
Hence ∠ADC = 110°
APPEARS IN
RELATED QUESTIONS
The following figure is parallelogram. Find the degree values of the unknown x, y, z.
Two adjacent angles of a parallelogram are as 1 : 2. Find the measures of all the angles of the parallelogram.
Two adjacent sides of a parallelogram are 4 cm and 3 cm respectively. Find its perimeter.
Which of the following statement is true for a rhombus?
It has two pairs of equal sides.
Which of the following statement is true for a rhombus?
It is a quadrilateral.
One side of a rhombus is of length 4 cm and the length of an altitude is 3.2 cm. Draw the rhombus.
The diagonals of a quadrilateral are of lengths 6 cm and 8 cm. If the diagonals bisect each other at right angles, what is the length of each side of the quadrilateral?
If opposite angles of a rhombus are (2x)° and (3x - 40)° then value of x is ______.
Draw a rhombus KLMN such that its side is 4 cm and m∠K = 75°.
In the figure, BEST is a rhombus, Then the value of y – x is ______.
