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ABCD is a parallelogram. O is the mid point of CD. ΔBOC ≅ ΔEOD by ______. - Mathematics

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Question

ABCD is a parallelogram. O is the mid point of CD. ΔBOC ≅ ΔEOD by ______.

Options

  • SSS

  • RHS

  • SAS

  • ASA

MCQ
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Solution

ABCD is a parallelogram. O is the mid point of CD. ΔBOC ≅ ΔEOD by ASA.

Explanation:


To prove that ΔBOC ≅ ΔEOD by ASA:

  • BO = EO  ...(Common side)
  • ∠BOC = ∠EOD  ...(Vertical angles)
  • OC = OD  ...(As O is the midpoint of CD in the parallelogram)

Thus, the two triangles are congruent by the ASA (Angle-Side-Angle) criterion.

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Chapter 8: Triangles - MULTIPLE CHOICE QUESTIONS [Page 93]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 8 Triangles
MULTIPLE CHOICE QUESTIONS | Q 10. | Page 93
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